-0.06x^2+2.7x+5.3=0

Solution for -0.06x^2+2.7x+5.3=0 equation:

-0.06x^2+2.7x+5.3=0

a = -0.06; b = 2.7; c = +5.3;
Δ = b2-4ac
Δ = 2.72-4·(-0.06)·5.3
Δ = 8.562
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.7)-\sqrt{8.562}}{2*-0.06}=\frac{-2.7-\sqrt{8.562}}{-0.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.7)+\sqrt{8.562}}{2*-0.06}=\frac{-2.7+\sqrt{8.562}}{-0.12}
$